Question

the sum of two consecutive multiples of 3 is 69 find them

Answer 1

Answer:

Let the first no. be "a"

Second No. be "a+3"

According to question  

a+a+3 = 69

2a+3=69

2a=69-3

2a =66

a=66/2

a =33

a+3=36

Therefore the numbers are 33 and 36

Answer 2

What are consecutive multiples of 3 ?

Example :-

3 , 6 , 9

So these are in the form a and a + 3

Multiples of 3 are numbers that are divisible by 3 .

Given :

Let the numbers be a and a + 3

a + a + 3 = 69

Find the values :

2 a + 3 = 69

= > 2 a = 69 - 3

= > 2 a = 66

= > a = 66/2

= > a = 33

Numbers

The numbers are a and a + 3

= > 33 and 33 + 3

= > 33 and 36.

$\mathfrak{\underline{ANSWER}}$

33 and 36.