Question

The sum of two consecutive multiples of 3 is 69. find these with full formula

Answer 1

let the multiples be 3x and 3(x+1) 
3x + 3(x+1) = 69
3x + 3x + 3 = 69
6x + 66
x = 11
multipes 3 x 11 = 33
                3 x 12 = 36

Answer 2

heya!!! here's your answer..
So let the first no. be x
So 2nd one is x+3
by question/ x+x+3=69
2x=66
therefore x=33
So the first multiple is 33 and second one is 36...