the sum of two consecutive multiples of 4 is 44 find them
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the sum of two consecutive numbers of 4 .
let the 2 consecutive numbers are
x + ( x + 1 )
4 ( x ) + 4( x + 1 ) = 44
4x + 4x + 4 = 44
8x + 4 = 44
8x = 44 - 4
8x = 40
x = 40 / 8
x = 5
substitute the value of x
4 ( 5 ) + 4 ( 5 + 1 ) = 44
20 + ( 20 + 4 ) = 44
20 + ( 24 ) = 44
44 = 44
1st consecutive number = 20
2nd consecutive number = 24
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