Question

The sum of two consecutive multiples of 4 is 68. Find them.

Answer 1

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Answer 2

let let the consecutive multiple of 4 be 4 x and 4 (x + 1)

➜4 x + (4 x + 1) = 68

➜4 x + 4 x + 4 = 68

➜8 x = 68 - 4

➜8x= 64

➜x=64/8

➜x=8

multiples of 4x equal 4 ×8 = 32

4 (x + 1) =4 (8 + 1 )= 36

Hence the consecutive number multiples of 4 are 32 and 36.