Question

the sum of two consecutive multiples of 4 is 68 .Find them

Answer 1

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Let the two consecutive number multiples of 4 are x and x+ 4

ATQ
$x + x + 4 = 68 \\ 2x = 68 - 4 \\ 2x = 64 \\ x = \frac{64}{2} \\ x = 32 \\ so \: other \: no \: is \\ 32 + 4 = 36$
Hence the consecutive number multiples of 4 are 32 and 36.

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Answer 2

Step-by-step explanation:

let let the consecutive multiple of 4 be 4 x and 4 (x + 1)

➜4 x + (4 x + 1) = 68

➜4 x + 4 x + 4 = 68

➜8 x = 68 - 4

➜8x= 64

➜x=64/8

➜x=8

multiples of 4x equal 4 ×8 = 32

4 (x + 1) =4 (8 + 1 )= 36

Hence the consecutive number multiples of 4 are 32 and 36.