The sum of two consecutive multiples of 5 is 315 find the multiples
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let them be 5x and 5 (x+1)
ATQ 5x+5 (x+1)=315
5x+5x+5=315
10x+5=315
x=(315-5)÷10
x=31
1st no is 5×31=155
2nd no is 5×(31+1)=5×32=160
ATQ 5x+5 (x+1)=315
5x+5x+5=315
10x+5=315
x=(315-5)÷10
x=31
1st no is 5×31=155
2nd no is 5×(31+1)=5×32=160
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