Question

the sum of two consecutive multiples of 5 is 55 the to multiple pulse r​

Answer 1

Given

The sum of two consecutive multiples of 5 is 55 Find the multiples

Solution

Let the consecutive number be 5x and 5(x + 1)

According to the given condition

$\implies\sf 5x + 5(x + 1)= 55 \\ \\ \implies\sf 5x + 5x + 5= 55 \\ \\ \implies\sf 10x + 5 = 55 \\ \\ \implies\sf 10x = 55 - 5 \\ \\ \implies\sf 10x = 50 \\ \\ \implies\sf x=\cancel\dfrac{50}{10} \\ \\ \therefore\sf x = 5$

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5x = 5 × 5 = 25

5(x + 1) = 5(5 + 1) = 30

Hence, 25 and 30 are the multiples

Answer 2

✯✯ QUESTION ✯✯

The sum of two consecutive multiples of 5 is 55 ..Find the multiples : -

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✰✰ ANSWER ✰✰

$\implies\tt{Let\:1st\:Cons.\:Multiple\:be=5x}$

$\implies\tt{Let\:2nd\:Cons.\:Multiple\:be=5(x+1)}$

$\implies\tt{Sum\:of\:Multiples=55}$

➥A.T.Q : -

$\implies\tt{5x+5(x+1)=55}$

$\implies\tt{5x+5x+5=55}$

$\implies\tt{10x+5=55}$

$\implies\tt{10x=55-5}$

$\implies\tt{10x=50}$

$\implies\tt{x=\cancel\dfrac{50}{10}}$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{x}\orange{=}\purple{5}}}$

➥Now ,

$\implies\tt{1st\:Multiple=5(5)}$

$\implies\tt\bold{25}$

$\implies\tt{2nd\:Multiple=5(5+1)}$

$\implies\tt{25+1}$

$\implies\tt\bold{26}$

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➥VERIFICATION : -

$\implies\tt{5(5)+5(5+1)=55}$

$\implies\tt{25+5(6)=55}$

$\implies\tt{25+30=55}$

$\implies\tt\bold{55=55}$

$\orange\longmapsto\:\large\underline{\boxed{\bf\red{L.H.S}\orange{=}\pink{R.H.S}}}$

✺ HENCE VERIFIED ✺