the sum of two consecutive multiples of 5 is 65. find the number
Answers
Answered by
112
Let the two consecutive multiples of 5 are
5(x + 1) and 5(x + 2)
According to the question,
5(x + 1) + 5(x + 2)= 65
=> 5x + 5 + 5x + 10= 65
=> 10x + 15= 65
=> 10x = 65 - 15
=> 10x = 50
=> x = 50/10
=> x = 5
Therefore, the two numbers are:
5(x + 1)
=5(5 + 1)
=25 + 5
= 30
5(x + 2)
= 5(5 + 2)
=25 + 10
= 35
PROOF: 30 + 35 = 65
5(x + 1) and 5(x + 2)
According to the question,
5(x + 1) + 5(x + 2)= 65
=> 5x + 5 + 5x + 10= 65
=> 10x + 15= 65
=> 10x = 65 - 15
=> 10x = 50
=> x = 50/10
=> x = 5
Therefore, the two numbers are:
5(x + 1)
=5(5 + 1)
=25 + 5
= 30
5(x + 2)
= 5(5 + 2)
=25 + 10
= 35
PROOF: 30 + 35 = 65
ranisoni60:
thanks
Answered by
26
The sum of two consecutive multiple of 5 is 5x and 10x
Then, 5x+10x=65
15x=65
X=65 divided into 15
X=13/3
Then, 5x+10x=65
15x=65
X=65 divided into 15
X=13/3
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