Question

The sum of two consecutive multiples of 6 is 114 find the smaller number ( I know the answer)

Answer 1

We know that multiple of 6 like =x+6
As you to add 6 to all multiple.to get next multiple

Let First and smallest multiple=x
Let next multiple=x+6

A/Q
x+x+6=114
2x=114-6
2x=108
x=108/2
x=54

So first number and smallest=54
second number=54+6=60

1st number=54 (smallest)
2nd number=60

Answer 2

Answer : 54

Step by Step Explanation :

Let the multiples be the xth, ( x+1)th multiples of 6 .

So ,

One of the multiple = 6 * x = 6x
Second multiple = 6 ( x + 1 ) = 6x + 6 .

Given ,

Sum of the multiples is 114 .

6x + ( 6x + 6 ) = 114

12x + 6 = 114

12x = 114 - 6

12x = 108

x = 9 .

Therefore ,

The multiples are 6( 9 ) , 6(9+1)

= 54 , 60

Hence , The smallest multiple is 54