the sum of two consecutive multiples of 8 is 56. The multiples
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4
Let them be 8x and 8(x+1)
thrn
8x + 8x+8 = 56
16x = 48
x = 48/16 = 3
thrn
no are
8×3 = 24 and 8(x+1) = 8(3+1) = 32
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Answered by
1
Let the two multiples of 8 be x+8 and x+16.
x+8+x+16 = 56
2x+24 = 56
2x=56-24
2x=32
x=32/2
x=16
Hence,the two consecutive multiples of 8 are:-
x+8 =16+8 =24
x+16 =16+16=32
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