The sum of two consecutive multiples of 8 is 88. Find these multiples
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Answer:
40 & 48
Step-by-step explanation:
Let x and x+8 be the two consecutive multiples of 8.
Given, x+x+8 =88
2x+8 =88
2x =80
x =40
x +8 =48
Therefore, the two consecutive multiples of 8 are 40 and 48.
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