The sum of two consecutive natural numbers and the square of the first is 5329. what are the numbers?
Answers
Answered by
2
Answer:
Let the two consecutive natural numbers be a and a+1.
According to the question,
⇒ a+(a+1)+a
2
=5329
⇒ 2a+1+a
2
=5329
⇒ a
2
+2a+1=5329
⇒ (a+1)
2
=5329
⇒ a+1=73
⇒ a=72
Thus, the two numbers are 72 and 73.
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Answered by
2
Answer:
x+x-1
x2 =5329
x=73
73+73+1
=73+74=143
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