Question

The sum of two consecutive natural numbers is 57 find the numbers (class 7th algabric expresion class 7th) ​

Answer 1

Answer:

The numbers are 28 and 29

Step-by-step explanation:

Let one number be x

And other be (x+1)

ATQ

X+x+1=57

2x=57-1

X=56/2

X=28

One number is x=28

And other number is =(x+1)=28+1=29

Hope it helps....

Answer 2

$\huge\bold{\mathtt{Question⇒}}$

The sum of two consecutive natural numbers is 57. Find the numbers.

$\huge\bold{\mathtt{Given⇒}}$

• The sum of two consecutive natural numbers is 57.

$\huge\bold{\mathtt{To\:find⇒}}$

The numbers.

$\huge\bold{\mathtt{Solution⇒}}$

Let one of the two numbers be x.

Since they are consecutive, the other number must be (x + 1).

Their sum = 57

According to condition,

x + (x + 1) = 57

Remove the bracket.

➳ x + x + 1 = 57

➳ 2x + 1 = 57

Subtract 1 from each side.

➳ 2x + 1 - 1 = 57 - 1

➳ 2x = 56

➳ x = $\frac{56}{2}$

➳ x = 28

$\huge\bold{\mathtt{Hence⇒}}$

x = 28

Substitute x with 28.

So, one number = x = 28

And, the other number

= (x + 1)

= (28 + 1)

= 29

$\huge\bold{\mathtt{Therefore⇒}}$

The two numbers are 28 and 29.

$\huge\bold{\mathtt{Confused??}}$

$\huge\bold{\mathtt{Verification⇒}}$

x + (x + 1) = 57

➳ 28 + 29 = 57

➳ 57 = 57

So, L.H.S = R.H.S.

Hence, verified.

$\huge\bold{\mathtt{Done}}$

$\large\bold{\mathtt{Hope\:this\:helps\:you.}}$

$\large\bold{\mathtt{Have\:a\:nice\:day.}}$