Question

the sum of two consecutive number is 43. find the smaller no​

Answer 1

Answer:

let first number = X

let second consecutive number = X + 1

their sum is = 43

X + X + 1 = 43

2x + 1 = 43

2x = 43 - 1

2x = 42

X = 42/2

X = 21 is Ur answer

smaller number = 21

second number = 21 + 1 = 22

Step-by-step explanation:

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Answer 2

Answer:

let the two consecutive number be x and x+1

=) x+(x+1)=43

2x+1=43

2x=43-1

2x=42

x=42/2

x=21

therefore the smaller number is 21 and the other number is (21+1)=22

Step-by-step explanation:

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