Question

the sum of two consecutive number is 91 . find the smaller number .​

Answer 1

Answer:

Let the two consecutive no be X,X+1

So the sum

$x + x + 1 = 91$

$2x + 1 = 91$

$2x = 90$

$x = \frac{90}{2}$

$x = 45$

so smallest no. is 45

Answer 2

Answer:

let the smaller no be x

larger no be x+1

•°•x+(x+1)=91

= x+x+1=91

= 2x = 91-1

= 2x = 90

= x = 45