Question

the sum of two consecutive number which was disabled by 7 are 343 and find both consecutive number​

Answer 1

$\underline{\underline{\huge{\gray{\tt{\textbf Answer :-}}}}}$

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$\sf\large\bold{\orange{\underline{\blue{ Given :-}}}}$

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• The sum of two consecutive number which when divided by 7 gives 343

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$\sf\large\bold{\orange{\underline{\blue{ To \: Find :-}}}}$

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• Let the two consecutive numbers be "x" and "x + 1"

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$\underline{\bold{\texttt{Sum of two consecutive number :}}}$

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➜ (x) + (x + 1)

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$\underline{\bold{\texttt{Sum of consecutive number divided by 7 :}}}$

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Given that the sum of two consecutive number which when divided by 7 gives 343

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So,

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➜ $\sf \dfrac { x + x + 1 } { 7 } = 343$

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➜ $\sf 2x + 1 = 343 \times 7$

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➜ 2x + 1 = 2401

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➜ 2x = 2401 - 1

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➜ 2x = 2400

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➜ $\sf x = \dfrac { 2400 } { 2 }$

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➨ x = 1200

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• Hence the two consecutive numbers are 1200 and 1201

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Answer 2

Correct Question :

The sum of two consecutive number which was divided by 7 are 343 and find both consecutive number.

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Solution :

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• Let one number = x
• Other number = x + 1

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A.T.Q :

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$\tt { \dfrac {x + x + 1}{7} = 343}$

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$: \implies \tt { 2x + 1 = 343 \times 7 }$

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$: \implies \tt { 2x = 2401 - 1 }$

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$: \implies \tt { 2x = 2400 }$

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$: \implies \tt { x = \dfrac {2400}{2}}$

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$: \implies \tt { x = 1200 }$

$\boxed {\tt One \: number \: = x = 1200 }$

$\boxed {\tt Other \: number \: = x + 1 = 1200 + 1 = 1201 }$