The sum of two consecutive numbers is 17 where as sum of there squares is 145 what is the product of the two numbers
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hello users....,
we have given that
sum of two consecutive numbers is 17 where as sum of there squares is 145
we have to find
the product of the numbers
solution:-
we know that
(a+b)² = a² +b² + 2ab
=> 2ab = (a+b)² - (a² +b²)
=> ab = [ (a+b)² - (a² +b²) ] /2
here
let the consecutive numbers are x and y
given that
x+y = 17 and x² +y² = 145
we have to find
xy = ?
now
product of the numbers =
xy = [(x+y)² - (x² + y²) ] /2
=> xy = [17² - 145 ] / 2
=> xy = (289 -145)/2
=> xy = 144 /2 = 72 answer
hence
the product of the two numbers = 72 answer
⭐⭐ hope it helps ⭐⭐
we have given that
sum of two consecutive numbers is 17 where as sum of there squares is 145
we have to find
the product of the numbers
solution:-
we know that
(a+b)² = a² +b² + 2ab
=> 2ab = (a+b)² - (a² +b²)
=> ab = [ (a+b)² - (a² +b²) ] /2
here
let the consecutive numbers are x and y
given that
x+y = 17 and x² +y² = 145
we have to find
xy = ?
now
product of the numbers =
xy = [(x+y)² - (x² + y²) ] /2
=> xy = [17² - 145 ] / 2
=> xy = (289 -145)/2
=> xy = 144 /2 = 72 answer
hence
the product of the two numbers = 72 answer
⭐⭐ hope it helps ⭐⭐
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0
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