The sum of two consecutive numbers is S.The square of larger minus the square of smaller number is
(a)S power 2 (b)2S (c)S (d)S+1
please tell the question step by step and explain and also try to tell fast.
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Answered by
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Consider two consecutive numbers like 5 and 6
5+6=11=S
larger number is 6 and smaller is 5
their squares are 36 and 25
36-25=11=S
option is c
5+6=11=S
larger number is 6 and smaller is 5
their squares are 36 and 25
36-25=11=S
option is c
Anonymous:
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Answered by
1
let the smaller number is Tn and larger number is Tn+1
given Tn + Tn+1 = s
numbers are consecutive hence Tn+1 - Tn = 1
Tn+1∧2 -Tn∧2 = (Tn+1 - Tn )(Tn+1 + Tn )
= 1*s
= s
hence (c) is correct
given Tn + Tn+1 = s
numbers are consecutive hence Tn+1 - Tn = 1
Tn+1∧2 -Tn∧2 = (Tn+1 - Tn )(Tn+1 + Tn )
= 1*s
= s
hence (c) is correct
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