Question

The sum of two consecutive numbers which was previously by 7 are 343 then find the both consecutive

Answer 1

Correct Question:

The sum of two consecutive numbers which was divided by 7 is 343, then find both the consecutive numbers.

Given:

✰ The sum of two consecutive numbers which was divided by 7 is 343.

To find:

✠ Both the consecutive numbers.

Solution:

First we will assume that the two consecutive numbers are x and x + 1 respectively. We know that when there sum is divided by 7, the result is equal to 343. Thus, by forming equation and doing required calculations, we can easily get the value of both the consecutive numbers.

Let's find out...♪

Let the two consecutive numbers are x and x + 1 respectively.

According to question,

➛ (x + x + 1)/7 = 343

➛ (2x + 1)/7 = 343

➛ 2x + 1 = 343 × 7

➛ 2x + 1 = 2401

➛ 2x = 2401 - 1

➛ 2x = 2400

➛ x = 2400/2

➛ x = 1200

∴ The first consecutive number = 1200

⟹ Second consecutive number = x + 1

⟹ Second consecutive number = 1200 + 1

⟹ Second consecutive number = 1201

∴ The second consecutive number = 1201

Both the consecutive numbers are 1200 and 1201 respectively.

_______________________________

Answer 2

Given,

• The sum of two consecutive numbers which Divided by 7 are 343.

To Find,

• The Consecutive number.

Solution,

Let's,

The First Number = X

So,

The Second Number = X + 1

The Sum of Both Number Divided by 7

The Sum of Both Number Divided by 7 = 343 •••(Given)

$: \implies \frac{(x )+ (x + 1)}{7} = 343 \\ \\ : \implies \frac{x + x + 1}{7} = 343 \\ \\ : \implies \frac{2x + 1}{7} = 343 \\ \\: \implies 2x + 1 = 343 \times 7 \\ \\ : \implies 2x + 1 = 2401 \\ \\: \implies 2x = 2401 - 1 \\ \\ : \implies 2x = 2400 \\ \\ : \implies x = \frac{2400}{2} \\ \\ : \implies \color{red} \boxed{x = 1200}$

Required Answer,

The First Number = X = 1200

The Second Number = X + 1 = 1200 + 1 = 1201