Question

The sum of two consecutive odd integers is 128. find

Answer 1

let one odd intger= x
than atq
its consecutive odd integer will be = x+2
we have sum of them = 128
so
x+ x +2= 128
2x= 126
x= 63
so one integer = 63
and its consecutive odd integer will be = 65

Answer 2

let the two consecutive no be =x&( x+2)
according to question
128=x+(x+2)
128=2x+2
128-2=2x
126=2x
126/2=x
63=x
so the required no is 63 & 63+2=65.