Question

the sum of two consecutive odd integers is 44 .fond the two integers

Answer 1

Answer:

The required consecutive numbers are 21,23.

Step-by-step explanation:

Here given sum of two consecutive odd integers is 44.

Let n be a odd number.

So two consecutive odd numbers are n,(n+2)

It is given that sum of these two numbers is 44.

According to question,

$n + (n + 2) = 44$

$2n + 2 = 44$

We are separating variable and constant part,

$2n = 44 - 2 \\ 2n = 42 \\ n = \frac{42}{2} \\ n = 21$

So, required consecutive numbers are 21 ,(21+2)=23.

This is a problem of Algebra.

Some important formulas of Algebra are

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Answer 2

Answer:

If the sum of two consecutive odd integers is 44 then the two integers are 21 and 23.

Step-by-step explanation:

• Let 2 two consecutive odd integers be:

       (2n+1),(2n+3)

       where n is any integer.

• According to the given problem, the sum of two consecutive odd integers is 44 .

• Hence we can write

  (2n+1)+(2n+3)=44

⇒ 4n+4=44

⇒ 4n=40

⇒ n=10

   using the value  n=10, we can write

  2n+1=21

  2n+3=23

• So, If the sum of two consecutive odd integers is 44 then the two integers are 21 and 23.

• ​Integers include all whole numbers with a positive and negative sign. so  if we include negative numbers along with whole numbers, It will form a set of integers.
• An integer includes no decimal or fractional part and it includes negative and positive numbers, including zero. Examples of integers are: -5, 0, 2, 5, 8, 77, and 1,043.

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