Question

The sum of two consecutive odd no. Is always divisible by 4

Answer 1

$\huge\boxed{\underline{\mathcal{\red{❥A}\green{N}\pink{S}\orange{W}\blue{E}\purple{R}}}}$

Verify this statement with the help of some examples.

3+ 5 = 8 and 8 is divisible by 4.

5 + 7 = 12 and 12 is divisible by 4.

Answer 2

$\huge{\dag}\:{\mathtt{Answer{\purple{\boxed{\sf{\purple{}}}}}}}$

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↦$\tt{3\:+\:5\:=\:8, \:which\: is \:divisible \:by \:4}$

↦$\tt{15\:+\:17\:=\:32,\: which\: is \:divisible }$$\tt{by \:4}$

↦$\tt{19\:+\:21\:=\:40, \:which \:is\: divisible}$$\tt{ by \:4.}$

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$\tt{Hence \:the \:statement \:the \:sum\: of }$$\tt{two\: consecutive\: odd \:numbers\: is }$$\tt{divisible\: by \:4 \:is\: verified.}$

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Hope its help uhh :)