Question

the sum of two consecutive odd number is 64 find the number​

Answer 1

Answer:

the two consecutive odd numbers whose sum is 64 are indeed 31 and 33.

Step-by-step explanation:

Let 2n + 1 = the first consecutive odd number, where n is an integer.

Let 2n + 3 = the second consecutive odd number.

Since "the sum of the two consecutive odd numbers is 64," we can translate this given information mathematically into the following equation to be solved for n as follows:

(2n + 1) + (2n + 3) = 64

2n + 1 + 2n + 3 = 64

Now, collecting like-terms on the left, we get:

4n + 4 = 64

Now, subtract 4 from both sides of the equation in order to begin isolating the unknown number, n, on the left side:

4n + 4 - 4 = 64 - 4

4n + 0 = 60

4n = 60

Now, divide both sides by 4 in order to isolate n on the left side and thus solve the equation for n:

(4n)/4 = 60/4

(4/4)n = 60/4

(1)n = 15

n = 15

Therefore, ...

2n + 1 = 2(15) + 1

= 30 + 1

= 31 and ...

2n + 3 = 2(15) + 3

= 30 + 3

= 33

CHECK:

(2n + 1) + (2n + 3) = 64

(31) + (33) = 64

31 + 33 = 64

64 = 64

Therefore, the two consecutive odd numbers whose sum is 64 are indeed 31 and 33.

Answer 2

The numbers are 31 , 33

Given :

The sum of two consecutive odd number is 64

To find :

Find the numbers

Solution :

Step 1 of 2 :

Form the equation to find the numbers

Let two consecutive odd numbers are x , x + 2

By the given condition

$\displaystyle \sf{ x + (x +2 ) = 64}$

Step 2 of 2 :

Find the numbers

$\displaystyle \sf{ x + (x +2 ) = 64}$

$\displaystyle \sf{ \implies 2x + 2 = 64}$

$\displaystyle \sf{ \implies 2x = 64 - 2}$

$\displaystyle \sf{ \implies 2x = 62}$

$\displaystyle \sf{ \implies x = \frac{62}{2} }$

$\displaystyle \sf{ \implies x = 31}$

First number = x = 31

Second number = x + 2 = 31 + 2 = 33

Hence two numbers are 31 , 33

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