The sum of two consecutive odd numbers in a set of three consecutive odd numbers is 7 more than the third number. what is the second of these numbers ?
Answers
Answered by
10
Answer:11
Step-by-step explanation:
let the 3 consecutive odd numbers be x, x+2 and x+4
acc to ques
x+x+2 = x+4+7
2x +2 = x +11
x=9
so the numbers are 9,11 and 13.
second number = 11
rajgiri1017:
Why we not take X,X+1,X+2.... instead of u took ....
because we need only odd numbers. adding 1 to an odd number will give an even number...consecutive odd numbers have a difference of 2.
k .k.
Answered by
0
Answer: The numbers are (-6),(-5) and (-4).
Step-by-step explanation:
- Let the three consecutive numbers be (x-1),x and (x+1).
- Given that sum of two numbers is 7 more than the third number.
- [x+1]-[(x-1)+x]=7
⇒[x+1]-[x-1+x]=7
⇒[x+1]-[2x-1]=7
⇒x+1-2x+1=7
⇒-x+2=7
⇒-x=7-2
∴ x=(-5)
The numbers will be (-5-1),(-5) and (-5+1) i.e.,(-6),(-5) and (-4).
- So,the required numbers are (-6),(-5) and (-4).
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