Question

the sum of two consecutive odd numbers is 40 the smaller one is​

Answer 1

HEre Is Your Ans ⤵

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Let the odd numbers be 2N + 1 and 2N + 3

According To the Question ,

➡2N + 1 + 2N + 3 = 40

➡4N + 4 = 40

➡4N = 36

➡N = 9

Thus , the odd numbers are 2N + 1 = 2 × 9 + 1 = 19 and 2N + 3 = 2 × 9 + 3 = 21

Therefore , The Smaller Number is $\fbox{19}$

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$<marquee > hope it helps u$

Answer 2

Step-by-step explanation:

let the consecutive numbers be x and x+2

then,

x+x+2=40

2x+2=40

2x=40-2

=38

x=38/2

=19

first number=x

=19

second number=x+2

=19+2=21