the sum of two consecutive odd numbers is 57 find the numbers
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an odd integer can be described as 2*n + 1 for some n, n an integer.
Therefore, we have to find n such that
(2*n + 1) + (2*n + 3) + (2*n + 5) = 57. Using algebra, we conclude that
6*n + 9 = 57, or 6*n = 48. Therefore, n = 8 and the numbers are
17, 19, 21. The crux of the problem is modeling the odd integer as 2*n + 1
got it??
x+(x+2)+(x+4)=57
3x+6=57
3x=51
x=17
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