the sum of two consecutive odd numbers is divisible by 4 verify the statement with help of the some examples
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Take a even number and let it be n. let's take two consecutive numbers after n which is n+1 and n+3.
Sum of two consecutive numbers =n+1+n+3=2n+4 which when divided by 4,we get no remainder as n is even and can be expressed as 2m where m is appropriate number. so divide 4m +4 by 4 we get remainder as zero and Quotient as m +1... let's take 3 and 5 .sum is 8 which leaves no remainder when divided by 4.. examples are (15,17),(19,21),(21,23)...etc
Hope it helps you....
Sum of two consecutive numbers =n+1+n+3=2n+4 which when divided by 4,we get no remainder as n is even and can be expressed as 2m where m is appropriate number. so divide 4m +4 by 4 we get remainder as zero and Quotient as m +1... let's take 3 and 5 .sum is 8 which leaves no remainder when divided by 4.. examples are (15,17),(19,21),(21,23)...etc
Hope it helps you....
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