The sum of two consecutive whole numbers is 43. The smaller number is _______.
Answers
Answered by
87
let one consecutive no. =x
other no. = x+1
A.T.Q
x+x+1 =43
2x=43-1
2x=42
x=42/2
x=21
hope it helps
other no. = x+1
A.T.Q
x+x+1 =43
2x=43-1
2x=42
x=42/2
x=21
hope it helps
Answered by
1
Answer:
21
Step-by-step explanation:
Given:- The given number is 43.
To find:- The smaller number in the two consecutive whole numbers whose sum will be 43.
Solution:-
Here the given number is 43.
We need to find the two consecutive numbers whose sum will be 43.
So let's consider the two consecutive whole numbers be y and y + 1.
According to the question,
y + (y + 1) = 43
⇒ 2y + 1 = 43
⇒ 2y = 43 - 1
⇒ 2y = 42
⇒ y = 42 ÷ 2
⇒ y = 21
The two consecutive numbers are 21 and 21 + 1 = 22.
To verify, 21 + 22 = 43.
Therefore, the smallest number is 21.
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