Question

the sum of two different number is 54 both number have 2 and 3 as their factories what are the possible numbers​

Answer 1

Step-by-step explanation:

Let’s take the numbers as X and Y.

X+Y=54

X(mod2)=0 and X(mod3)=0

Both X and Y are divisible by 6. Therefore:

X=6K K=1,2,…,8

Y=6m m=1,2,…,8

I am assuming neither of these numbers is zero.

Then just plug for different values of m and K.

Note: Since 54 is divisible by 6 then 54 minus any multiple of 6 will be divisible by 6. Therefore every possible value of K and m are solutions.

K=1, m=8 → X=6 and Y=48

K=2, m=7 → X=12 and Y=42

K=3, m=6 → X=18 and Y=36

K=4, m=5 → X=24 and Y=30