Question

the sum of two digit no. and no. obtain by reversing the order of its digit is 165 if the digit differ by 3 find the no.

Answer 1

let the no.=10x+y-------(1)
no. in reverse order=10y+x-----(2)
given that (1)+(2)=165
10x+y+10y+x=165
11(x+y)=165
x+y=165/11=15--------(3)
given that difference between digits=3
x-y=3------(4)
now,(3)+(4)=>2x=15+3
x=9 sub.in(3) we get y=15-9=6
sub.x=9;y=6 in(1) we get
required no.=10x+y=10(9)+6=96.
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