Question

the sum of two digit no and number obtained by reversing the digits id 55.If the digits of no differ by 1 find the number

Answer 1

Heya Friend ✋✋✋

Let 'x' be its tens digit

and 'y' be its ones digit

The sum of number and number obtained after reversing it

10x + y + 10y + x = 55

11x + 11y = 55

x + y = 5 .......(1)

Digit of the number differ by 1

so....

x - y = 1

x = y + 1 .....(2)

From (1) and (2)

y + 1 + y = 5

2y = 4

y = 2.....


x = y + 1 = 3.....


The number is 32

hope it helps