the sum of two-digit no. and the no. obtained by reversing the digit is 66. If the digits of the no. differ by 2, find the no. How many such no. are there?
Answers
Answered by
6
10x+y +10y+x =66
11x+11y=66. i eq
if x>y than
x-y =2. ii eq
11x+11y=66
11x-11y=22
22x=88
x= 4and than y=2
and if y>x
than x= 2 and y=4
11x+11y=66. i eq
if x>y than
x-y =2. ii eq
11x+11y=66
11x-11y=22
22x=88
x= 4and than y=2
and if y>x
than x= 2 and y=4
Answered by
3
let unit digit be y
let tens digit be x
number=10x+y
According to the question
(10x+y)+(10y+x)=66
=11x+11y=66
=x+y=6-------------(1)
it is also given that x-y=2 -------(2)
from eq. 1 and 2
x+y=6
x-y=2
---------
2x=8
x=4
now put the value of x=4 in eq. (1)
x+y=6
4+y=6
y=2
now put value of y and x in (10x+y)
no. is 42
Please mark it brainliest
let tens digit be x
number=10x+y
According to the question
(10x+y)+(10y+x)=66
=11x+11y=66
=x+y=6-------------(1)
it is also given that x-y=2 -------(2)
from eq. 1 and 2
x+y=6
x-y=2
---------
2x=8
x=4
now put the value of x=4 in eq. (1)
x+y=6
4+y=6
y=2
now put value of y and x in (10x+y)
no. is 42
Please mark it brainliest
bhanu33:
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