Math, asked by SimranGill, 1 year ago

the sum of two-digit no. and the no. obtained by reversing the digit is 66. If the digits of the no. differ by 2, find the no. How many such no. are there?

Answers

Answered by Rishita24
6
10x+y +10y+x =66
11x+11y=66. i eq
if x>y than
x-y =2. ii eq
11x+11y=66
11x-11y=22
22x=88
x= 4and than y=2
and if y>x
than x= 2 and y=4
Answered by bhanu33
3
let unit digit be y
let tens digit be x
number=10x+y
According to the question
(10x+y)+(10y+x)=66
=11x+11y=66
=x+y=6-------------(1)


it is also given that x-y=2 -------(2)
from eq. 1 and 2
x+y=6
x-y=2
---------
2x=8
x=4


now put the value of x=4 in eq. (1)
x+y=6
4+y=6
y=2


now put value of y and x in (10x+y)
no. is 42

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bhanu33: for what
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