Question

The sum of two digit no is 13 .If the number is subtracted from the one obtained by interchanging the digits, the result is 45. what is the number.

Linear equation in two variables.

Please solve fast

Answer 1

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Equations are=> first=>◆x+y=13◆,second=>●x-y=45●
by using elimination method =>
x+y=13
x- y=45
- + -
________
2y=-32
y= -32/2=-16
◆putting this value of y in first equation so,
the equation is x+y=13
x+(-16)=13
x=13+16
x=29
hence, x and y are equal to x=29,y =-16

Answer 2

Here is your solution

Given :-
The sum of two digit number is 13 .
if the number is subtracted from the one obtained by interchanging the digits the results is 45 .

Let
The two digits be x and y.

Number is 10x + y 

x + y = 13 (given)

y = 13 – x --------------1

A/q

10y + x – (10x + y) = 45

9y – 9x = 45

y – x = 5 --------------2

putting the value of y from equation 1 in eqn 2

13 – x – x = 5

13 – 2x = 5

2x = 8

x = 4✔

y = 13 – 4 = 9✔

The two-digit number = 10x + y = (10 × 4) + 9 = 49.

Hope it helps you.