Question

The sum of two digit no. Is 8 the no. Obtained by interchange the digits exceeds the given no. By 18 . Find given no.

Answer 1

Heya friend,

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Let the digits at ones place be x. Then,

the digits at tens place = (8-x)

Original number = 10(8-x) + x

= 80 - 10x + x

= 80 - 9x

On interchanging the digits

new number obtained = 10x + 8-x

= 9x + 8

According to question,

New number - Original number = 18

9x + 8 - (80-9x) = 18

=> 9x + 8 - 80 + 9x = 18

=> 18x - 72 = 18

=> 18x = 18 + 72

=> 18x = 90

=> x = 90/18

=> x = 5

Hence, the digits at ones place is 5.

The digits at tens place = (8-5) = 3.

So, the original number is 35 and the new number is 53.

Thanks

Answer 2

Hello Mate !


Here's your answer


Your question is wrong


Correct Question :-

The sum of two - digit number is 8. The number obtained by interchanging the digits exceeds the given number by 18. Find the given number .


Solution :-

Let unit place digit be x .


Ten's place digit = ( 8 - x )

Number = x + 10 ( 8 - x )

=> x + 80 - 10 x

=> - 9 x + 80


Number obtained by enterchanging the digits = 10 x + 8 - x

=> 9 x + 8


As per the condition ,

( 9x + 8 ) - ( - 9x + 80 ) = 18

9 x + 8 + 9 x - 80 = 18

18 x = 18 + 72

18 x = 90

x = 5

Unit place digit = 5 and ten's place digit = 8 - 5

=> 3

Hence ,

The required number = 5 + 3 * 10

=> 35