Question

the sum of two digit no is 9 on reversing its digits the new number obtained is 45 more tha orignal no find the no

Answer 1

Answer:

let the digits are x and y,the number is 10x+y

here, x+y=9

on reversing it's digits the new number is

10y+x

10y+x-45=10x+y

10y-y+x-10x=45

9y-9x=45

9(y-x)=45

y-x=45/9=5

y=5+x

here x+y=9

x+5+x=9

2x=9-5=4

x=4/2=2

y=5+2=7

so the original number is 27