Question

the sum of two digit no is 9.The number is 6 times the unit digit .find the no.

Answer 1

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The sum of two digit number is 9.
t + u = 9
u = (9-t)
The number is 6 times the unit digit.
10t + u = 6u
10t + u - 6u = 0
10t - 5u = 0
10t - 5(9-t) = 0
10t - 45 + 5t = 0
10t + 5t = 45
15t = 45
t = 45/15
t = 3 is the tens digit
then
9-3 = 6 is units digit

Answer 2

Answer:

let the units place digit be x

thus tens place digit is 9-x

so the number: 10(9-x)+x*1 = 90-10x +x = 90-9x

number = 6x (given)

so, 6x = 90-9x

15x = 90

x=6

number is 6x = 6*6 =36

Step-by-step explanation: