Question

the sum of two digit no. obtained by reversing the order in digit is 121 and the two digit differ by 3. find the no.​

Answer 1

Let the unit digit is ‘x’ and the 10th digit is ‘y’

The number is 10 y +x

Reversed number is 10 x+y

Given 11 x+11 y =121`

x+y=11 [dividing by 11]…….1

Also x-y=3 ……2

solving 1 and 2 we get

x=7 and y=4

The number is 47 [check 47+74=121, 7–4=3]