Question

the sum of two digit number and a number obtained by reversing the order of its digit is 88 express in linear equation

Answer 1

Answer:

10x + y + 10y + x =88

Step-by-step explanation:

Let the 2 digit number be 10x+y.

Given:    The sum of two digit number and a number obtained by reversing the order of its digit is

=> 10x + y + 10y + x =88

Answer 2

let one's digit = x
ten's digit = y
acc. to question
(10y+x) + ( 10x +y) = 88