Question

The sum of two digit number and number obtained to be interchange its digit is 110. If 10 is subtracted from the first number the new number is 4 more than 5 times the sum of the digit of first number. Find the first number

Answer 1

(10y+x)+(10x+y)=110

11x+11y=110 (or) x+y=10−−−(1)

Also,

4x−5y+14=0

4x−5y=−14−−−−−−−(2)

Solving equation (1) & (2), we get:

x=4 and y=6

Hence the number is 64.