The sum of two digit number and number obtained to be interchange its digit is 110. If 10 is subtracted from the first number the new number is 4 more than 5 times the sum of the digit of first number. Find the first number
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(10y+x)+(10x+y)=110
11x+11y=110 (or) x+y=10−−−(1)
Also,
4x−5y+14=0
4x−5y=−14−−−−−−−(2)
Solving equation (1) & (2), we get:
x=4 and y=6
Hence the number is 64.
11x+11y=110 (or) x+y=10−−−(1)
Also,
4x−5y+14=0
4x−5y=−14−−−−−−−(2)
Solving equation (1) & (2), we get:
x=4 and y=6
Hence the number is 64.
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