Question

The sum of two digit number and the number formed by interchanging its digit is 88 of the sum of sum and difference of the digit of the number is 8

Answer 1

Answer:

Let the tens place digit be x

let the ones place digit be y

Then the number would be 10x+y

If the digits are interchanged the number would be 10y+x

Its given that sum of these 2 numbers is 88.

10x+y+10y+x=88

11x+11y=88

x+y=8   -------A (let this be equation A)

Sum of digits=x+y

Difference of digits=x-y

x+y+x-y=8 (as given)

2x=8

x=4

Now putting the value of x in equation A we get

x+y=8

4+y=8

y=4

Hence the number is 10x+y = 10(4)+4=44

44 is the number.