Question

the sum of two digit number and the number formed by reversing the digits is 110 and the difference of the digits is 6 find the number​

Answer 1

82!

82+28 is 110

8-2 gives us 6

Hence answer is 82...

Hope that helped

Answer 2

Answer:

82

Given:

Sum of two digit after reversing is 110 and their difference is 6

To find:

The number

Solution:-

Let ten's digit be 10x and unit digit be y

The number=10x+y

After reversing=10y+x

According to question

10x+y+10y+x=110

11x+11y=110

11(x+y)=110

x+y=10 .......i)

Now given;

x-y=6 ......ii)

Solving i) and ii)

x+y+x-y=10+6

2x=16

x=8

Putting value in x+y=10

8+y=10

y=10-8

y=2

x=8 and y=2

__________________

Therefore the original number=10x+y

=10×8+2

=80+2

=82