Question

the sum of two digit number and the number formed by interchanging its digits is 110 if 10 is subtracted from the first number the new number is 4 more than five times of the sum of digits is the first number find the first number
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Answer 1

Step-by-step explanation:

Here is your solution

Let the digit at ones place = y

Let the digit at tens place = x

original number = 10x + y

Number formed by reversing the digits =10y + x

On adding original number and Reversed number.

10x+y+10y+x = 110

11x + 11y = 110

11 (x + y ) = 110

x + y = 10

x = 10 - y ................................................. (1)

on subtracting 10 from the original number , we get = 10x + y -10

and

4 more than 5 times the sum of digits = 5(x + y) + 4

A/q

10x + y -10 = 5(x + y) + 4

10x + y -10 = 5x +5y + 4

10x -5x + y -5y = 10 +4

5x - 4y = 14.................................................. (2)

putting the value of x in equation (2)

5x - 4y = 14

5×(10-y) - 4y = 14

50-5y-4y =14

-9y = 14 -50

-9y = -36

y = 4

Now

x = 10-y

x = 10 - 4

x = 6

original number or first numbe = 10x + y = 10×6+4 = 64

Hope it helps you

Answer 2

Answer:

64 is the answer

Step-by-step explanation:

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