The sum of two digit number and the number obtained be reversing the of its digit is 121 and the two digits differ by 3.Find the numbers.
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Answered by
10
Answer:
Step-by-step explanation:
Let, the tens and ones digits be x and y, respectively such that x>y.
The original number is (10x+y) and the number obtained by reversing the order of digits is (10y+x).
Now, (10x+y)+(10y+x)=121
Or, 11(x+y)=121
Or, x+y=11 …(1)
Also, x-y=3 (given) …(2)
Solving eq. (1)and (2)
We get, x=7 and y=4.
So, the required number is 74 or, 47.
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Answered by
2
Let 2-digits Are X and Y
then
10y +x is the Number
and 10x+y is Reversed Number
so
10x+x + 10y +y =121
x+y=11
And X-Y =3
so
2x=14
x=7
And 7-y=3
So y=4
possible Number is 47 and 74
then
10y +x is the Number
and 10x+y is Reversed Number
so
10x+x + 10y +y =121
x+y=11
And X-Y =3
so
2x=14
x=7
And 7-y=3
So y=4
possible Number is 47 and 74
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