Question

The sum of two digit number and the number obtained be reversing the of its digit is 121 and the two digits differ by 3.Find the numbers.

Answer 1

Answer:

Step-by-step explanation:

Let, the tens and ones digits be x and y, respectively such that x>y.

The original number is (10x+y) and the number obtained by reversing the order of digits is (10y+x).

Now, (10x+y)+(10y+x)=121

Or, 11(x+y)=121

Or, x+y=11 …(1)

Also, x-y=3 (given) …(2)

Solving eq. (1)and (2)

We get, x=7 and y=4.

So, the required number is 74 or, 47.

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Answer 2

Let 2-digits Are X and Y
then
10y +x is the Number
and 10x+y is Reversed Number
so
10x+x + 10y +y =121
x+y=11

And X-Y =3
so
2x=14
x=7

And 7-y=3
So y=4
possible Number is 47 and 74