Question

The sum of two digit number and the number obtained by reversing the objects is 66. If the digits differ by 2 find the number

Answer 1

Hi !

Let the unit's place by x and ten's place be y .
The number would be 10y+ x

the no: when digits are reversed :  10x + y

given ,

10y + x + 10x + y = 66
11x + 11y = 66
x + y = 6       ----> [1]

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Given , 
adding
x - y = 2 ----> [2]

adding equations 1 and 2 ,
x -y = 2
x+ y = 6
--------------------

2x  = 8
x = 4

x + y = 6

4 + y = 6

y = 2

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The no: is :-

10y + x 

10× 2 + 4 = 20 + 4 = 24

the no: is 24


 

Answer 2

Answer:

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