Question

the sum of two digit number and the number obtained by reversing the digit s is 66 if the digits of the number differs by 2, find the number how many such numbers are there​

Answer 1

Answer:

let the ten digit no ,and unit digit no be x and y respectievely.

Step-by-step explanation:

then

required no be (10x+y)

A.T.Q

(10x+y) +(10y+x)=66••••[1]

x-y=2••••••••••••••••••••[2]