Question

the sum of two digit number and the number obtained by reversing the order of its digits is 121 and the two digits differ by 3 find the number​

Answer 1

Answer:74 and 47

Step-by-step explanation:

Answer 2

✞︎ Given :-

• The sum of two digit number and the number obtained by reversing the order of its digits is 121
• And the two digits differ by 3

❦︎ To find :-

The numbers........

✯︎ Solution :-

Let the two numbers be 'x' and 'y'

➪︎ Then the number is 10x + y

The number obtained by reversing the digits is yx

➪︎ Then the number is 10y + x

❁︎ According to problem,

Sum of them is 121....

➪︎ So, 10x + y + 10y + x = 121

➪︎ 11x + 11y = 121

➪︎ 11 ( x + y ) = 121

➪︎ x + y = 11.......(1)

⍟︎ And also given that,

The numbers are differ by 3

➪︎ So, x - y = 3.........(2)

By adding (1) & (2)

➪︎ x + y = 11

➪︎ x - y = 3

___________

2x = 14

x = 7

Substitute x = 7 in (1) ,

➪︎ 7 + y = 11

➪︎ y = 11 - 7

➪︎ y = 4

So, the numbers is xy = 74 ; yx = 47

✰︎ The required numbers are 74 and 47...