Question

The sum of two digit number and the number obtained by reversing its digits is 121.Find the number of its units place is 5

Answer 1

Answer:

65+56=121

Let no. be t5

reverse will be 5t

t*10 + 5 + 5*10 + t = 11t + 55 = 121 => 11t = 66 => t = 6

Answer 2

Answer:

The number = 65

Step-by-step explanation:

Given,

The sum of a two-digit number and the number obtained by reversing its digits is 121.

The number in unit place  = 5

Solution:

Let 'x' be the digit in the tens place and 'y' be the digit in the unit place

Then the number is 10x+y

The number obtained by reversing the digit = 10y+x

Then by the given condition, we have

10x+y+10y+x = 121

11x+11y = 121

11(x+y) = 121

x+y = $\frac{121}{11}$ = 11

x+y = 11 ----------(1)

Also, given the number in the unit place is 5, then we have y = 5

substituting the value of 'y' in equation (1) we get

x+5 = 11

x = 11 -5 = 6

∴x = 6

Hence the required number = 10x+y = 10×6+5 = 65

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