Question

the sum of two digit number and the number obtained by reversing the order and its digit is 143 the digit at tens place is greater than the digit at unit place by 3 find the original number ​

Answer 1

Answer:

85

Step-by-step explanation:

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if it did please thank and mark brailiest

Answer 2

Answer:

$let \: the \: original \: number \: be \: 10x + y \\ \\ as \:p er \: the \: question \\ \\ = > x - y = 3.............(1) \\ \\ and \\ \\ = > 10x + y + 10y + x = 143 \\ = > 11x + 11y \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 143 \\ = > x + y = 13.....................(2) \\ \\ solving \: (1) \: and \: (2) \\ x + y = 13 \\ x - y = 3 \\ ................. \\ = > 2y = 10 \\ = > y = 5 \\ \\ from \: eq(1) \\ = > x = 3 + y \\ = > x = 3 + 5 \\ = > x = 8 \\ \\ the \: original \: number \: is \: 10 \times 8 + 5 \: i.e \: 85$