The sum of two digit number and the number obtained by interchaging the digit is 99. If the digit of tens place exceeds the digit at unit place at three.
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Step-by-step explanation:
Let the digit in the unit's place be x and the digit in the ten's place be y . Then,
Number=10y+x
The number obtained by interchanging the digits is 10x+y
According to the given conditions,
(10y+x)+(10x+y)=99
=11x+11y=99
=x+y=9 ......1
And,x−y=±3 ......2 (given)
On solving equation 1 and 2 ,we get
x=6,y=3 or x=3,y=6
Hence the required number is either63 or 36
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