Math, asked by samratajaysingh08, 4 months ago

the sum of two digit number and the number obtained by reversing the digit is 66.if the digit of the number differ by 2find the number .how many numbers are there​

Answers

Answered by anshukumar90060
0

Answer:

the number Will be 42

answer is 42

Answered by Ashwinop1
0

Answer:

24 and 42

Step-by-step explanation:

Let the two digit be x and y

∴ Number (2−digit) =10×x+y

Sum of 2−digit and reverse of it

⟹10x+y+10y+x=66 (given)

∴x+y=6 (equation 1)

Digits differ by 2

∴x−y=2 (equation 2)

On adding,

2x=8

⟹x=4

∴y=2

or, x+y=6 From 1 equation

and y−x=2 From 2 equation

On adding:

2y=8

y=4

x=2

∴ Two digit numbers are: 42 and 24

There are two such numbers.

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